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<id>http://www.freebase.com/view/chemistry/chemical_compound</id>

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<title>Freebase: Discussion about Chemical Compound</title>

<updated>2008-11-22T01:46:44Z</updated>

<entry >
      <author ><name>faye</name>
<uri>http://www.freebase.com/view/user/faye</uri>
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    <content type="html">&lt;p&gt;Hi pepper55,&lt;/p&gt;&lt;p&gt;I'm afraid Freebase isn't a Q&amp;amp;A web site. I also have a feeling -- although I'm not the person to ask about Chemistry -- that the answer to your question is not something straight-forward like &amp;quot;42&amp;quot;, but involves calculation using the correct formula and substituting variables with the correct values. On the Internet in general, you're more likely to encounter people just as clueless (or even more so) regarding your homework.&lt;/p&gt;&lt;p&gt;I encourage you to consult your textbook, and seek out your teachers and classmates on this. Really, your best bet is people familiar with your course material and resources right at school. Your professor or TA probably holds office hours where questions like this can be answered and explained in detail, within the proper context. The building that houses the Chemistry department probably has the highest concentration of people who can help you with this homework assignment than almost anywhere else in the world -- take advantage of that! &lt;/p&gt;&lt;p&gt;Good luck!&lt;/p&gt;</content>

    
    <id>http://www.freebase.com/view/guid/9202a8c04000641f8000000009cdd193</id>

    <link title="2-Methylhexane: Help" href="http://www.freebase.com/view/guid/9202a8c04000641f8000000009cdd193" rel="alternate" type="text/html"  />


    
    
    
    <summary type="html" >Hi pepper55, I'm afraid Freebase isn't a Q&amp;amp;A web site. I also have a feeling -- although I'm not...</summary>

    <title>2-Methylhexane: Help</title>

    <updated>2008-11-21T19:22:00.0013Z</updated>

</entry>
<entry >
      <author ><name>pepper55</name>
<uri>http://www.freebase.com/view/user/pepper55</uri>
</author>

    
    <content type="html">&lt;p&gt;Help me, I'm lost in Chemsitry and can't afford to fail this class.&amp;nbsp; My prof says we're to find the energy of 2 methylhexane.&amp;nbsp; What's he talking about?&lt;/p&gt;</content>

    
    <id>http://www.freebase.com/view/guid/9202a8c04000641f8000000009adae5c</id>

    <link title="2-Methylhexane: Help" href="http://www.freebase.com/view/guid/9202a8c04000641f8000000009adae5c" rel="alternate" type="text/html"  />


    
    
    
    <summary type="html" >Help me, I'm lost in Chemsitry and can't afford to fail this class.&amp;nbsp; My prof says we're to...</summary>

    <title>2-Methylhexane: Help</title>

    <updated>2008-11-14T01:11:45.0017Z</updated>

</entry>
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